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de Sitter space and the equivalence betweenf(R)and scalar-tensor gravity

2007/03/26 by Valerio Faraoni · 205 citations
Mathematics · Physics and Astronomy · #Advanced Differential Geometry Research #Anti-de Sitter space #Black Holes and Theoretical Physics #Cosmology and Gravitation Theories #De Sitter universe #Geometry #Homogeneous #Mathematical physics #Mathematics #Metric (unit) #Philosophy #Physics #Quantum mechanics #Scalar (mathematics) #Space (punctuation) #Statistical physics #Universe #gr-qc

paper · pdf · doi:10.1103/physrevd.75.067302

published in Physical review. D. Particles, fields, gravitation, and cosmology/Physical review. D. Particles and fields 75(6) (American Physical Society) · 4 pages, revtex, to appear in Phys. Rev. D. Revised version contains additional and updated references

arxiv created 2007/03/26 · openalex publication_date 2007/03/26 · arxiv updated 2009/12/01 · openalex created_date 2017/03/16 · openalex updated_date 2026/08/05

Abstract

It is shown that, when f^\ensuremath'\ensuremath'\ensuremath≠0, metric f(R) gravity is completely equivalent to an \ensuremathω=0 scalar-tensor theory with respect to perturbations of de Sitter space, contrary to previous expectations. Moreover, the stability conditions of de Sitter space with respect to homogeneous and inhomogeneous perturbations coincide in most scalar-tensor theories, as is the case in metric f(R) gravity.

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