2026/07/07 by Rongqi Xiao, Xiaodong Jia · 1 voice
Mathematics · #math.GN
In this paper, we study when the Smyth powerspace Q^*v(X) of a topological space X is coherent, and prove that X is coherent and weakly Hausdorff if and only if Q^*v(X) is coherent and weakly Hausdorff. We give examples to show that neither coherence nor weak Hausdorffness of X solely implies that Q^*v(X) is coherent or weakly Hausdorff. As a byproduct, our work gives an affirmative answer to a question raised by Xu.