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Are theX(4160)andX(3915)charmonium states?

2009/12/27 by Youchang Yang, You-chang Yang, Zurong Xia +1 · 1 citation
Mathematics · Physics and Astronomy · #Algorithm #Bar (unit) #High-Energy Particle Collisions Research #Mathematics #Nuclear physics #Particle physics #Particle physics theoretical and experimental studies #Physics #Quantum Chromodynamics and Particle Interactions #Quantum mechanics #Quark #Spectrum (functional analysis) #State (computer science) #hep-ph

paper · pdf · doi:10.1103/physrevd.81.094003

published as Phys.Rev.D81:094003,2010 · 9 pages, 8 figures

arxiv created 2009/12/27 · openalex publication_date 2010/05/05 · arxiv updated 2010/05/25 · openalex created_date 2016/06/24 · openalex updated_date 2026/08/05

Abstract

Inspired by the newly observed states X(4160) and X(3915), we analyze the mass spectra of these states in different quark models and calculate their strong decay widths by the 3P0 model. According to the mass spectra of charmonium states predicted by the potential model, the states \ensuremathχ0(33P0), \ensuremathχ1(33P1), \ensuremathηc2(21D2), \ensuremathηc(41S0) all can be candidates for the X(4160). However, only the decay width of the state \ensuremathηc2(21D2) in our calculation is in good agreement with the data reported by Belle, and the decay of \ensuremathηc2(21D2)\ensuremath→DD, which is not seen in experiment, is also forbidden. Therefore, it is reasonable to interpret the charmonium state \ensuremathηc2(21D2) as the state X(4160). For the state X(3915), although the mass of \ensuremathχ0(23P0) is compatible with the experimental value, the calculated strong decay width is much larger than experimental data. Hence, the assignment of X(3915) to the charmonium state \ensuremathχ0(23P0) is disfavored in our calculation.

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