2026/07/18 by Suman Saurabh
#math.GT
For N≥1, let KN be the annular closure of (σ1σ2-1)N. We prove that triply graded annular Khovanov homology over \mathbb F2 detects the underlying unoriented annular link KN. If 3\nmid N, the only ambiguity is overall orientation reversal. If 3| N, the only ambiguity is independent reversal of components; every such reorientation has the same homology, so this is sharp. The proof combines braid detection from the extremal annular grading with a rigidity theorem: the Jones polynomial and exponent sum determine (σ1σ2-1)N up to conjugacy in B3.