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Two model-independent results for the momentum dependence of ϱ-ω mixing

1995/06/28 by Kim Maltman · 2 citations
Physics and Astronomy · #Charge (physics) #High-Energy Particle Collisions Research #Isospin #Mathematical physics #Meson #Mixing (physics) #Momentum (technical analysis) #Nuclear physics research studies #Nucleon #Omega #Particle physics #Physics #Propagator #Quantum Chromodynamics and Particle Interactions #Quantum mechanics #Rho meson #Symmetry breaking #Unitarity #Vector meson #nucl-th

paper · pdf · doi:10.1016/0370-2693(95)01208-8

published as Phys.Lett. B362 (1995) 11-16 · 14 pages, uses REVTEX Entire manuscript available as a ps file at http://www.physics.adelaide.edu.au/theory/home.html Also available via anonymous ftp at ftp://adelphi.adelaide.edu.au/pub/theory/ADP-95-35.T189.ps

arxiv created 1995/06/28 · openalex publication_date 1995/11/01 · arxiv updated 2009/12/01 · openalex created_date 2016/06/24 · openalex updated_date 2026/08/05

Abstract

Two model-independent results on the momentum-dependence of ρ-ω mixing are described. First, an explicit choice of interpolating fields for the vector mesons is displayed for which both the mixing in the propagator and the isospin-breaking at the nucleon-vector meson vertices (and hence also the one-vector-meson-exchange contribution to NN charge symmetry breaking) vanish identically at q2=0. Second, it is shown, using the constraints of unitarity and analyticity on the spectral function of the vector meson propagator, that there is no possible choice of interpolating fields for the ρ0, ω0 mesons such that, with the ρω element of the propagator defined by Δρωμν(q2)= (gμν-qμqν/q2)θ(q2)/(q2-m2ρ)(q2- m2ω), θ(q2) is independent of momentum. It follows that the standard treatment of charge symmetry breaking in few-body systems cannot be interpreted as arising from any realizable effective meson-baryon Lagrangian and must, therefore, be considered purely phenomenological in content.

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