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Chambers of arrangements of hyperplanes and Arrow's impossibility theorem

2006/08/31 by Hiroaki Terao
Engineering · Mathematics · #Arrow #Arrow's impossibility theorem #Calculus (dental) #Combinatorics #Computer science #Discrete mathematics #Hyperplane #Impossibility #Law #Mathematical economics #Mathematics #Mathematics and Applications #Point processes and geometric inequalities #Political science #Social choice theory #graph theory and CDMA systems #math.CO #msc:32S22 #msc:91B14

paper · pdf · doi:10.1016/j.aim.2007.02.006

published as Advances in Math. 214 (2007), 366-378

arxiv created 2007/02/10 · openalex publication_date 2007/03/04 · arxiv updated 2009/12/01 · openalex created_date 2025/10/10 · openalex updated_date 2026/08/05

Abstract

Let \mathcal A be a nonempty real central arrangement of hyperplanes and \rm \bf Ch be the set of chambers of \mathcal A. Each hyperplane H defines a half-space H+ and the other half-space H-. Let B = \+, -\. For H∈ \mathcal A, define a map εH+ : \rm \bf Ch → B by εH+ (C)=+ (if C⊆ H+) and εH+ (C)= - (if C⊆ H-). Define εH-=-εH+. Let \rm \bf Chm = \rm \bf Ch×\rm \bf Ch×...×\rm \bf Ch (mtimes). Then the maps εH± induce the maps εH± : \rm \bf Chm → Bm . We will study the admissible maps Φ: \rm \bf Chm → \rm \bf Ch which are compatible with every εH±. Suppose |\mathcal A|≥ 3 and m≥ 2. Then we will show that \mathcal A is indecomposable if and only if every admissible map is a projection to a omponent. When \mathcal A is a braid arrangement, which is indecomposable, this result is equivalent to Arrow's impossibility theorem in economics. We also determine the set of admissible maps explicitly for every nonempty real central arrangement.

Citations