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Defining binary phylogenetic trees using parsimony: new bounds

2023/03/06 by Mirko Wilde, Mareike Fischer, Wilde, Mirko +1
Biochemistry, Genetics and Molecular Biology · Earth and Planetary Sciences · #05-08 #05C05 #05C90 #92-08 #92B05 #Combinatorics (math.CO) #Evolution and Paleontology Studies #FOS: Biological sciences #FOS: Mathematics #Genetic diversity and population structure #Genomics and Phylogenetic Studies #Populations and Evolution (q-bio.PE)

paper · pdf · doi:10.48550/arxiv.2303.03238

openalex publication_date 2023/03/06 · openalex created_date 2025/10/10 · openalex updated_date 2026/07/28

Abstract

Phylogenetic trees are frequently used to model evolution. Such trees are typically reconstructed from data like DNA, RNA, or protein alignments using methods based on criteria like maximum parsimony (amongst others). Maximum parsimony has been assumed to work well for data with only few state changes. Recently, some progress has been made to formally prove this assertion. For instance, it has been shown that each binary phylogenetic tree T with n ≥ 20k leaves is uniquely defined by the set Ak(T), which consists of all characters with parsimony score k on T. In the present manuscript, we show that the statement indeed holds for all n ≥ 4k, thus drastically lowering the lower bound for n from 20k to 4k. However, it has been known that for n ≤ 2k and k ≥ 3, it is not generally true that Ak(T) defines T. We improve this result by showing that the latter statement can be extended from n ≤ 2k to n ≤ 2k+2. So we drastically reduce the gap of values of n for which it is unknown if trees T on n taxa are defined by Ak(T) from the previous interval of [2k+1,20k-1] to the interval [2k+3,4k-1]. Moreover, we close this gap completely for the nearest neighbor interchange (NNI) neighborhood of T in the following sense: We show that as long as n≥ 2k+3, no tree that is one NNI move away from T (and thus very similar to T) shares the same Ak-alignment.

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