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A Random-Player Game and Derangement Numbers

2024/02/15 by Yehonatan Fridman, Fridman, Yehonatan
Economics, Econometrics and Finance · #Combinatorics (math.CO) #FOS: Mathematics #Game Theory and Voting Systems #Probability (math.PR)

paper · pdf · doi:10.48550/arxiv.2402.10246

openalex publication_date 2024/02/15 · openalex created_date 2025/10/10 · openalex updated_date 2026/07/28

Abstract

Consider the following game between a random player R and a deterministic player D. There is a pile of n elements at the beginning. The rules for playing are as follows: In each turn of R, if the pile contains exactly m elements, R removes k elements from the pile, where k is independently identically distributed from 1, . . . , m. In each turn of D, D removes only one element. The winner is the player that, at the end of its round, has no elements remaining. R starts first to play. This short paper shows that Dn, which is defined as the probability of D winning the game (when is initialized with n elements), approaches 1/e when n increases; and more specifically, Dn = dn/n!, where dn is the n-th derangement number.

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