Explanation of the mass of the muon

2001/10/02 by E. L. Koschmieder, Koschmieder, E. L.
Physics and Astronomy · #FOS: Physical sciences #General Physics (physics.gen-ph) #physics.gen-ph

paper · pdf · doi:10.48550/arxiv.physics/0110005

7 pages. See: arXiv hep-lat/0104016, hep-lat/0002016, hep-ph/0002179

arxiv created 2001/10/02 · arxiv updated 2009/12/01

Abstract

The difference of the rest masses m(pi⁺-) - m(mu⁺-) is nearly equal to 1/4 of the rest mass of the pi^(+-) mesons and is equal to the sum of the rest masses of the 0.7 times 10⁹ muon neutrinos (respectively anti-muon neutrinos) which are in the cubic lattice of the pi^(+-) mesons according to the standing wave model. In the decay of a pi^(+) or pi^(-) meson all muon neutrinos, respectively anti-muon neutrinos, of the cubic lattice of the pi^(+-) mesons are emitted. The sum of the oscillation energies of all neutrinos in the pi^(+-) mesons is the same as the sum of the oscillation energies of the remaining neutrinos in the mu^(+-) mesons. Consequently the mass of the mu^(+-) mesons is equal to m(pi⁺-) - 0.7 times 10⁹ m(nu_mu) or 0.75 times m(pi⁺-), within 1% in agreement with the measured ratio m(mu⁺-) / m(pi⁺-) = 0.757028.

Related

• The mass of the tau neutrinos
• The rest masses of the electron and muon and of the stable mesons and baryons
• The masses of the mesons and baryons. Part V. The neutrino branch particles
• Muon decay and neutrino mass
• Muon Oscillations